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0=-0.8x^2+10x+2
We move all terms to the left:
0-(-0.8x^2+10x+2)=0
We add all the numbers together, and all the variables
-(-0.8x^2+10x+2)=0
We get rid of parentheses
0.8x^2-10x-2=0
a = 0.8; b = -10; c = -2;
Δ = b2-4ac
Δ = -102-4·0.8·(-2)
Δ = 106.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-\sqrt{106.4}}{2*0.8}=\frac{10-\sqrt{106.4}}{1.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+\sqrt{106.4}}{2*0.8}=\frac{10+\sqrt{106.4}}{1.6} $
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